CSIR NET Previous Question Papers with Answers are included here. Check the Old Papers & CSIR UGC NET Study Material to make your preparation perfect. Preparation Tips, syllabus & exam pattern also available here in this article along with the CSIR NET Old Papers. So, the intenders can download previous papers & start the preparation instantly.
CSIR UGC NET Question Papers
CSIR NET Solved Question Papers shall help participants get better preparation. It is for sure that with the help of the CSIR NET Previous Question Papers contenders can get good marks in the exam. Also, syllabus and Exam pattern in the below sections which makes participants preparation more effective. So, take the help of the old papers during the preparation of the exam. Get the last 10 years CSIR UGC NET Papers here in this article.
We updated subject wise CSIR NET Previous Year Papers for convenience. So, participants can prepare easily for the exam by considering the subjects applied for. We provided CSIR NET Solved Papers to make the contender’s preparation easy. Check the below available links to find CSIR NET Previous Year Question Papers. Free PDF’s of CSIR NET Exam Papers are available in the provided links. Click on the links and get CSIR NET Question Papers to prepare perfectly for the written exam.

CSIR NET Old Year Question Papers
| Exam Conducting Authority | National Testing Agency | 
| Exam Name | CSIR-UGC NET December 2025 | 
| Exam Type | Eligibility Test | 
| No of Papers | 05 (Five) | 
| Mode of Examination | Computer Based Test (CBT) | 
| Pattern of Examination | Objective Type with MCQ | 
| Application Period | 25th September to 24th October 2025 | 
| Exam Date | 18th December 2025 | 
| Page Category | Previous Papers | 
| Official Website | csirnet.nta.ac.in | 
Download CSIR NET Previously Asked Questions
Candidates can refer the previous year’s question papers for the best exam preparation. Actually, by doing this the aspirants become more familiar with the exam pattern and the important subjects from which the questions are asked most of the time. In fact the candidates can create a strategy by solving the question papers from previous years. Also, the aspirants can practice the previous year’s memory-based question papers for Life Science, Chemical Science, Physical Science, and Mathematical Science subjects of the CSIR NET 2025.
Candidates can get the confidence to attempt the exam by referring the previous papers. We also giving answers for the CSIR NET Assistant Previous Papers. So, easily prepare for the exam with the provided CSIR UGC NET Question Papers with Answers. CSIR NET Practice Question Papers plays an important role in the preparation of the exam. So, take the help of the CSIR NET Previously Asked Questions and Answers while preparing for the exam.
Free Download CSIR NET Previous Question Papers
- December 2023 Chemical Science Paper
- CSIR NET Earth Science December 2023 Paper
- CSIR NET Life Science December 2023 Paper
- CSIR NET Mathematical Science December 2023 Paper
- CSIR NET Physical Science December 2023 Paper
- CSIR NET Engineering Science December 2014 Paper
- Click Here for more Previous Papers
Preparation Tips for CSIR UGC NET Exam
Start your preparation now by referring given CSIR UGC NET Preparation Tips which are given below. With the help of the provided CSIR UGC NET Preparation Tips, participants can get good results in the exam. So, begin your preparation by taking the help of the CSIR NET Preparation Tips. Step by step procedure is given here help you to prepare perfectly for the exam.
- Start Practicing by downloading CSIR UGC NET Old Year Papers with Answers.
- Download CSIR UGC NET Syllabus 2025 PDF from the below link.
- Also, check the below Exam Pattern table to know the mark details of the Subjects to prepare well for the exam.
- To complete the syllabus before the exam, aspirants must prepare a schedule.
- Don’t miss the timetable & practice all given CSIR NET Previous Years Question Papers.
- Also, try CSIR NET Mock Tests to improve your preparation level, speed and accuracy.
CSIR UGC NET Previous Papers
With the practice of the CSIR NET Old Year Papers, postulants can improve their speed and Accuracy easily. Also, within the few time, participants can answer questions which are going to appear in the exam with the help of the Previous Years Question Papers. NTA is going to conduct the CSIR UGC NET to select the contenders for the post of the Assistant Professors. So, postulants can prepare well for the exam to crack the CSIR UGC NET Question Papers. The intenders have a chances to get good marks in the exam if they practice with the CSIR NET Frequently Asked Questions and Answers.
| CSIR NET Links | |
| Notification | CSIR NET Notification | 
| Application Form | CSIR NET Application Form | 
| Exam Pattern | CSIR NET Exam Pattern | 
| Syllabus | CSIR NET Syllabus | 
| Previous Papers | CSIR NET Previous Papers | 
| Exam City Intimation | CSIR NET City Intimation | 
| Admit Card / Exam Date | CSIR NET Admit Card | 
| Answer Keys | CSIR NET Answer Keys | 
| Results | CSIR NET Result | 
CSIR NET Syllabus According to Subjects
Check the below CSIR UGC NET Syllabus 2025 to begin your preparation. Start your preparation now by knowing CSIR NET Syllabus 2025. It is compulsory for the contenders to know the subjects included in the CSIR UGC NET Syllabus. To help the contenders, we also provided syllabus along with the CSIR NET Old Papers.
- Chemical Sciences
- Earth Sciences
- Life Sciences
- Mathematical Sciences
- Physical Science
Exam Pattern of CSIR NET According to Subjects
| Subject Code | Subjects of the Test | 
| 701 | Chemical Sciences | 
| 702 | Earth, Atmospheric, Ocean and Planetary Sciences | 
| 703 | Life Sciences | 
| 704 | Mathematical Sciences | 
| 705 | Physical Sciences | 
The CSIR UGC NET will consist of three parts. All the parts will consist of objective type, multiple choice questions. There will be no break between papers. The subject-wise scheme of examination is as per details below:
- The MCQ test paper of each subject shall carry a maximum of 200 marks.
- The exam shall be for duration of three hours.
- The question paper shall be divided in three parts.
- The Paper will be in bilingual i.e. Hindi and English
| Chemical Sciences (701) | Part A | Part B | Part C | Total | 
| Total questions | 20 | 40 | 60 | 120 | 
| Max No of Questions to attempt | 15 | 35 | 25 | 75 | 
| Marks for each correct answer | 2 | 2 | 4 | 200 | 
| Marks for each incorrect answer (Negative marking for part A, B & C is @ 25%) | 0.5 | 0.5 | 1 | – | 
| Earth, Atmospheric Ocean & Planetary Sciences (702) | Part A | Part B | Part C | Total | 
| Total questions | 20 | 50 | 80 | 150 | 
| Max No of Questions to attempt | 15 | 35 | 25 | 75 | 
| Marks for each correct answer | 2 | 2 | 4 | 200 | 
| Marks for each incorrect answer (Negative marking for part A & B is@25% and part C is @ 33%) | 0.5 | 0.5 | 1.32 | – | 
| Life Sciences (703) | Part A | Part B | Part C | Total | 
| Total questions | 20 | 50 | 75 | 145 | 
| Max No of Questions to attempt | 15 | 35 | 25 | 75 | 
| Marks for each correct answer | 2 | 2 | 4 | 200 | 
| Marks for each incorrect answer (Negative marking for part A, B & C is @25%) | 0.5 | 0.5 | 1 | – | 
| Mathematical Sciences (704) | Part A | Part B | Part C | Total | 
| Total questions | 20 | 40 | 60 | 120 | 
| Max No of Questions to attempt | 15 | 25 | 20 | 60 | 
| Marks for each correct answer | 2 | 3 | 4.75 | 200 | 
| Marks for each incorrect answer (Negative marking in Part A & B is @ 25%; no negative marking in Part C) | 0.5 | 0.75 | 0 | – | 
| Physical Sciences (705) | Part A | Part B | Part C | Total | 
| Total questions | 20 | 25 | 30 | 75 | 
| Max No of Questions to attempt | 15 | 20 | 20 | 55 | 
| Marks for each correct answer | 2 | 3.5 | 5 | 200 | 
| Marks for each incorrect answer (Negative marking for part A, B & C is @25%) | 0.5 | 0.875 | 1.25 | – | 
Aspirants can check the CSIR UGC NET Previous Papers along with the Syllabus & Exam Pattern, Admit Cards and Notification Details etc. Stick our rrbapply.com page to get instant updates on State Govt & Central Govt Jobs. Keep in touch with us by giving a comment in the below appeared comment box.
 
					
 
