CSIR NET December 2025 Notification is officially released at the NTA website @ https://csirnet.nta.ac.in/. Candidates willing to appear for the CSIR-UGC NET December 2025 Exam can register from 21st September 2025. The Council of Scientific Research has entrusted the National Testing Agency (NTA) with the task of conducting of Joint CSIR-UGC NET December 2025 which is a test to determine the eligibility of Indian nationals for award of Junior Research Fellowship and appointment as Assistant Professor and admission to Ph.D. only in Indian universities and colleges. Details of CSIR-UGC NET Eligibility and Application Form is available in the section below. Thus, scroll down for the details.
Overview of CSIR-UGC NET 2025 Notice
| Exam Name | Council of Scientific and Industrial Research National Eligibility Test |
| Conducting Body | National Testing Agency |
| Exam Level | National |
| Exam Frequency | Twice a year |
| December 2025 Exam Application | 25th September to 24th October 2025 |
| Exam Mode | Online (CBT Mode) |
| Exam Duration | 180 minutes |
| Total Questions | 120-150 MCQs |
| Official website | csirnet.nta.ac.in |
| Helpline No | 011 40759000 |
CSIR-UGC NET Notification
CSIR NET is an eligibility test that is conducted to determine the eligibility of a candidate for Junior Research Fellowship (JRF) and for Lectureship (LS) /Assistant Professor in Indian universities and colleges. As per the official notification, the CSIR NET is conducted for 5 Science Subjects only: Life Sciences, Chemical Sciences, Mathematical Sciences, Physical Sciences, and Earth Sciences. This exam is conducted twice and CSIR NET December 2025 application process began on 25th September 2025.
The National Testing Agency (NTA) released the official notification for CSIR NET Dec 2025 Examination on 25th September 2025. The application process started on 25th September 2025. The notification PDF contains important details such as the exam dates, eligibility criteria, application process, syllabus, exam pattern, and other relevant information. For complete details the interested candidates can visit the official website for CSIR NET @ csirnet.nta.ac.in and download the notification.
| CSIR NET Links | |
| Notification | CSIR NET Notification |
| Application Form | CSIR NET Application Form |
| Exam Pattern | CSIR NET Exam Pattern |
| Syllabus | CSIR NET Syllabus |
| Previous Papers | CSIR NET Previous Papers |
| Exam City Intimation | CSIR NET City Intimation |
| Admit Card / Exam Date | CSIR NET Admit Card |
| Answer Keys | CSIR NET Answer Keys |
| Results | CSIR NET Result |
CSIR NET Eligibility Conditions
The CSIR NET Eligibility Conditions ensure that only candidates who have the necessary educational qualifications and meet other requirements are allowed to appear for the exam. Interested candidates must be familiar with the CSIR NET eligibility, which specifies the educational qualification, age limit, and number of attempts.
CSIR NET Age Limit
As discussed above that CSIR NET is conducted for Junior Research Fellowship and appointment as Assistant Professor. Thus, age limit for registration according to the job profile is as follows –
| Job Profile | Upper Age Limit | ||
| Reserved Category | OBC (NCL) | SC/ST/PwD/Women | |
| JRF | 28 years | 31 years | 33 years |
| Assistant Professor | No Upper Age Limit | ||
Educational Qualification
- General (UR), General-EWS, and OBC candidates must possess an M.Sc. or an equivalent degree, an integrated BS-MS, a BS-4-year degree, a BE, a B.Tech, a B. Pharma, or an MBBS with at least 55% marks.
- Candidates from the SC/ST and Persons with Disabilities (PwD) categories must receive at least 50% in their M.Sc. or comparable degree, Integrated BS-MS, BS-4 years, BE, B. Tech, B. Pharma, or MBBS, or an equivalent degree.
- Candidates with a B.Sc. (Hons.) or an equivalent degree who are currently enrolled in an integrated MS-Ph.D. program and have. received a minimum of 55% of their marks for General students (and 50% of their marks for SC, ST, and PWD candidates) are also eligible to take the CSIR NET exam.
- If a bachelor’s degree holder enrolls in a Ph.D. or integrated Ph.D. program within two years, they are eligible for the fellowship.
| Categories | Percentage of marks for CSIR NET |
| General Category | At least 55% marks in M.Sc. or Integrated BS-MS |
| SC/ST/OBC Category | A Minimum of 50% in M.Sc. or B.Sc. with admission in Integrated MS-PhD. |
How to apply for CSIR NET 2025?
The Application Process for CSIR NET 2025 involves three process – Registration, Fill the Online Application and Finally paying the application fee. In the first phase, the interested candidates should complete the registration at the official website which will be required for the subsequent stages compulsorily. Stage Wise application process is as follows –
| Registration Process | 1. At first visit the official website of NTA CSIR NET @ https://csirnet.nta.ac.in/. 2. Click on Registration Link. 3. Enter the basic details like email registration ID, mobile number etc. 4. Finally, submit the application. 5. The candidate will get the Registration ID and Password. |
| Filling the Application Form | 1. In this phase, login to the portal with the registration. 2. Fill up the details like education, communication address, subjects, preferred exam city etc. 3. Also upload the scanned images of photograph & signature. 4. Recheck the details and submit the application. 5. Candidates will get the confirmation of application submission. |
| Payment of Application Fees | 1. Navigate to the application fees section. 2. Select the category wise payment option. 3. Pay the application fees through the mode as per the preference. 4. Finally, wait for the confirmation. 5. Thus, the CSIR NET Application form submission is complete. |
CSIR NET Application Fee
Candidates during the application need to pay the fee for CSIR NET 2025 online by Debit/Credit Card/UPI or Internet Banking through any of the payment gateway of SBI/ICICI. The category-wise application fee is available for reference.
| Category | Application Fee |
| General | INR 1150 |
| General-EWS/OBC(NCL) | INR 600 |
| SC/ ST/ PwD/ Third Gender | INR 325 |
CSIR NET 2025 – Important Links
Here are the link to download the CSIR-UGC NET Information Bulletin and Application link. Interested Candidates can refer these to submit the application within the deadline.
| Information Bulletin Download | Click Here |
| Apply Online Link | Click Here |
CSIR NET December Exam 2025 – Important Dates
Keep an eye on the important dates of CSIR UGC NET December 2025 Exam through the table shared below. We for the sake of candidates shall update the chart according to the official announcement.
| Online Registration Period | 25th September to 24th October 2025 |
| Last Date for Fee Paymeny | 25th October 2025 |
| Correction of Application Form | 27th to 29th October 2025 |
| City Intimation Slip | 10 days earlier |
| Downloading of Admit Card | 2 to 3 days earlier |
| Date of Examination Schedule | 18th December 2025 |
| Display of Answer Keys | Update Later |
| Declaration of Result on NTA Website | Update Later |
Exam Pattern of CSIR NET According to Subjects
| Subject Code | Subjects of the Test |
| 701 | Chemical Sciences |
| 702 | Earth, Atmospheric, Ocean and Planetary Sciences |
| 703 | Life Sciences |
| 704 | Mathematical Sciences |
| 705 | Physical Sciences |
The CSIR UGC NET will consist of three parts. All the parts will consist of objective type, multiple choice questions. There will be no break between papers. The subject-wise scheme of examination is as per details below:
- The MCQ test paper of each subject shall carry a maximum of 200 marks.
- The exam shall be for duration of three hours.
- The question paper shall have three parts.
- The Paper will be in bilingual i.e. Hindi and English
| Chemical Sciences (701) | Part A | Part B | Part C | Total |
| Total questions | 20 | 40 | 60 | 120 |
| Max No of Questions to attempt | 15 | 35 | 25 | 75 |
| Marks for each correct answer | 2 | 2 | 4 | 200 |
| Marks for each incorrect answer (Negative marking for part A, B & C is @ 25%) | 0.5 | 0.5 | 1 | – |
| Earth, Atmospheric Ocean & Planetary Sciences (702) | Part A | Part B | Part C | Total |
| Total questions | 20 | 50 | 80 | 150 |
| Max No of Questions to attempt | 15 | 35 | 25 | 75 |
| Marks for each correct answer | 2 | 2 | 4 | 200 |
| Marks for each incorrect answer (Negative marking for part A & B is@25% and part C is @ 33%) | 0.5 | 0.5 | 1.32 | – |
| Life Sciences (703) | Part A | Part B | Part C | Total |
| Total questions | 20 | 50 | 75 | 145 |
| Max No of Questions to attempt | 15 | 35 | 25 | 75 |
| Marks for each correct answer | 2 | 2 | 4 | 200 |
| Marks for each incorrect answer (Negative marking for part A, B & C is @25%) | 0.5 | 0.5 | 1 | – |
| Mathematical Sciences (704) | Part A | Part B | Part C | Total |
| Total questions | 20 | 40 | 60 | 120 |
| Max No of Questions to attempt | 15 | 25 | 20 | 60 |
| Marks for each correct answer | 2 | 3 | 4.75 | 200 |
| Marks for each incorrect answer (Negative marking in Part A & B is @ 25%; no negative marking in Part C) | 0.5 | 0.75 | 0 | – |
| Physical Sciences (705) | Part A | Part B | Part C | Total |
| Total questions | 20 | 25 | 30 | 75 |
| Max No of Questions to attempt | 15 | 20 | 20 | 55 |
| Marks for each correct answer | 2 | 3.5 | 5 | 200 |
| Marks for each incorrect answer (Negative marking for part A, B & C is @25%) | 0.5 | 0.875 | 1.25 | – |
Stat tuned as we shall bring the subsequent updates for the intenders. Meanwhile, the intenders can also look for various Central Govt, State Govt and PSU Jobs through this portal.
